Workaround for backslash in multilines

[gorecfile.git] / w.go

diff --git a/w.go b/w.go
index 9057f8dbc33a33892098fd9bbb52345924489968..32ee966c1e22e14454866f5366c08ff3ac304d25 100644 (file)
--- a/w.go
+++ b/w.go
@@ -1,6 +1,6 @@
 /*
 recfile -- GNU recutils'es recfiles parser on pure Go
-Copyright (C) 2020-2022 Sergey Matveev <stargrave@stargrave.org>
+Copyright (C) 2020-2023 Sergey Matveev <stargrave@stargrave.org>
 
 This program is free software: you can redistribute it and/or modify
 it under the terms of the GNU General Public License as published by
@@ -37,7 +37,9 @@ func (w *Writer) RecordStart() (written int, err error) {
 func (w *Writer) WriteFields(fs ...Field) (written int, err error) {
        var n int
        for _, f := range fs {
-               n, err = w.w.WriteString(f.Name + ": " + strings.TrimLeft(f.Value, " ") + "\n")
+               n, err = w.w.WriteString(
+                       f.Name + ": " + strings.TrimRight(strings.TrimLeft(f.Value, " "), "\\") + "\n",
+               )
                written += n
                if err != nil {
                        return
@@ -48,13 +50,15 @@ func (w *Writer) WriteFields(fs ...Field) (written int, err error) {
 
 func (w *Writer) WriteFieldMultiline(name string, lines []string) (written int, err error) {
        var n int
-       n, err = w.w.WriteString(name + ": " + strings.TrimLeft(lines[0], " ") + "\n")
+       n, err = w.w.WriteString(
+               name + ": " + strings.TrimRight(strings.TrimLeft(lines[0], " "), "\\") + "\n",
+       )
        written += n
        if err != nil {
                return
        }
        for _, l := range lines[1:] {
-               n, err = w.w.WriteString("+ " + l + "\n")
+               n, err = w.w.WriteString("+ " + strings.TrimRight(l, "\\") + "\n")
                written += n
                if err != nil {
                        return